请教一个shell脚本的命令行参数问题

utstar

bash-3.00# cat 1.sh
#!/bin/sh

echo \[$0\] number of args = $#
echo \[$0\] args = $*
./2.sh $*

bash-3.00# cat 2.sh
#!/bin/sh

echo \[$0\] number of args = $#
echo \[$0\] args = $*


bash-3.00# ./1.sh "\"hello world\" test"
[./1.sh] number of args = 1
[./1.sh] args = "hello world" test
[./2.sh] number of args = 3
[./2.sh] args = "hello world" test

我想让1.sh的命令行参数原封不动的传送给2.sh, 要怎么写？请大虾帮忙

netman網中人

將 $* 改為 "$@" (不能省掉雙引號哦！)