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gtk编程里面怎么key_release_event不管用阿

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发表于 2003-10-20 11:15:18 | 显示全部楼层 |阅读模式
button press什么的是好使的,为什么键盘的不行ni?

/* File: gdkdrawing.c */
/* example from gtk+ package */
#include <gtk/gtk.h>

static GdkPixmap *pixmap = NULL;

static gint configure_event( GtkWidget *widget,GdkEventConfigure *event)
{
if (pixmap) gdk_pixmap_unref(pixmap);

pixmap = gdk_pixmap_new(widget->window,
widget->allocation.width,
widget->allocation.height,
-1);
gdk_draw_rectangle (pixmap,
widget->style->white_gc,
TRUE,
0, 0,
widget->allocation.width,
widget->allocation.height);

return TRUE;
}

static gint expose_event( GtkWidget *widget, GdkEventExpose *event )
{
gdk_draw_pixmap(widget->window,
widget->style->fg_gc[GTK_WIDGET_STATE (widget)],
pixmap,
event->area.x, event->area.y,
event->area.x, event->area.y,
event->area.width, event->area.height);

return FALSE;
}

static void draw_brush( GtkWidget *widget, gdouble x, gdouble y)
{

update_rect.x = x - 5;
update_rect.y = y - 5;
update_rect.width = 10;
update_rect.height = 10;
gdk_draw_rectangle (pixmap,
widget->style->black_gc,
TRUE,
update_rect.x, update_rect.y,
update_rect.width, update_rect.height);
gtk_widget_draw (widget, &update_rect);
}

static gint button_press_event( GtkWidget *widget,GdkEventButton *event)
{
printf("button press\n");
if (event->button == 1 && pixmap != NULL)
draw_brush (widget, event->x, event->y);

return TRUE;
}

void quit ()
{
gtk_exit (0);
}

int main( int argc, char *argv[] )
{
GtkWidget *window;
GtkWidget *drawing_area;
GtkWidget *vbox;
GtkWidget *button;

//初始化
gtk_set_locale();
gtk_init (&argc, &argv);

window = gtk_window_new (GTK_WINDOW_TOPLEVEL);
gtk_widget_set_name (window, "Drawing Area");

vbox = gtk_vbox_new (FALSE, 0);
gtk_container_add (GTK_CONTAINER (window), vbox);
gtk_widget_show (vbox);

gtk_signal_connect (GTK_OBJECT (window), "destroy",
GTK_SIGNAL_FUNC (quit), NULL);

//建立绘图区
drawing_area = gtk_drawing_area_new ();
gtk_drawing_area_size(GTK_DRAWING_AREA(drawing_area), 200, 200);
gtk_box_pack_start(GTK_BOX(vbox), drawing_area, TRUE, TRUE, 0);
gtk_widget_show (drawing_area);

//建立信号触发
gtk_signal_connect (GTK_OBJECT (drawing_area), "expose_event",
(GtkSignalFunc) expose_event, NULL);
gtk_signal_connect (GTK_OBJECT(drawing_area),"configure_event",
(GtkSignalFunc) configure_event, NULL);
gtk_signal_connect (GTK_OBJECT(drawing_area),"key_release_event"
,
(GtkSignalFunc) keypress_event, NULL);
gtk_signal_connect (GTK_OBJECT (drawing_area),
"motion_notify_event",
(GtkSignalFunc) motion_notify_event, NULL);
gtk_signal_connect (GTK_OBJECT (drawing_area),
"button_press_event",
(GtkSignalFunc) button_press_event, NULL);

//设置事件掩码
gtk_widget_set_events (drawing_area, GDK_EXPOSURE_MASK
| GDK_LEAVE_NOTIFY_MASK
| GDK_BUTTON_PRESS_MASK
| GDK_POINTER_MOTION_MASK
| GDK_POINTER_MOTION_HINT_MASK
| GDK_KEY_RELEASE_MASK
| GDK_KEY_PRESS_MASK );

button = gtk_button_new_with_label ("退出");
gtk_box_pack_start (GTK_BOX (vbox), button, FALSE, FALSE, 0);

gtk_signal_connect_object (GTK_OBJECT (button), "clicked",
GTK_SIGNAL_FUNC (gtk_widget_destroy),
GTK_OBJECT (window));
gtk_widget_show (button);

gtk_widget_show (window);

gtk_main ();

return 0;
}
发表于 2003-10-20 12:11:32 | 显示全部楼层
将key_release_event联到window的事件中
改成
gtk_signal_connect (GTK_OBJECT(window),"key_release_event"
,(GtkSignalFunc) keypress_event, NULL);
为什么drawing_area构件不能接收键盘的事件,哪个高人可否指点一下?
 楼主| 发表于 2003-10-20 14:00:58 | 显示全部楼层

搞定了,多谢!

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